[J3] ac-implied-do + const-expr — question on expansion of such arrays

[Malcolm Cohen]

Yes it is a constant expression.

 

It is actually very clear, as item (12) it “what can go into a constant expression” is

   “an ac-do-variable within an array constructor where each scalar-int-expr of the corresponding ac8

implied-do-control is a constant expression”

 

Cheers,

-- 

..............Malcolm Cohen, NAG Oxford/Tokyo.

 

From: J3 <j3-bounces at mailman.j3-fortran.org> On Behalf Of Tobias Burnus via J3
Sent: Thursday, October 15, 2020 5:53 AM
To: General J3 interest list <j3 at mailman.j3-fortran.org>
Cc: Tobias Burnus <burnus at net-b.de>
Subject: [J3] ac-implied-do + const-expr — question on expansion of such arrays

 

Hi,

the following issue came up – and it was unclear whether
"kind=i" is a "constant expression" or not when used as
follows.

In terms of compilers, one accepts it and two reject it.

If one first checks the expression itself, then "i" is
an ac-do-variable not not really constant for kind=i,
not fulfilling the constraint for kind=; while the int(i)
part is fine for 'int' (not constant but also not required).
If after this checking, the array is expanded, everything
else becomes known and simplifies to an array of numbers.

However, if the array is first expanded and then the values
are checked for constness, kind=n1 and kind=n2 are fine.

What's the proper interpretation?

use iso_fortran_env
integer, parameter :: n1 = minval(integer_kinds)
integer, parameter :: n2 = maxval(integer_kinds)
integer, parameter :: A(*) = [integer :: (int(A=i, kind=i), i=n1,n2,n2-n1)]
print *, A
end


Tobias



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