(j3.2006) defining a type with no components

Bill Long longb
Thu Apr 17 18:24:22 EDT 2014


On Apr 17, 2014, at 5:15 PM, Dan Nagle <danlnagle at me.com> wrote:

> Hi,
> 
> On Apr 17, 2014, at 16:03 , Bill Long <longb at cray.com> wrote:
> 
>> Is the simple act of including a declaration sufficient to cause
>> the result to ?be defined by the function??
> 
> Well, 2.3.5 at [35:8-9] says the <<specification-part>> of a procedure
> is evaluated when execution involves execution of the procedure.

I assume [33:7-8].  It says that specification expressions in the <specification-part> are evaluated.  I don?t see any specification expressions.

Cheers,
Bill

> 
> So yes.
> 
> --
> 
> Cheers!
> Dan Nagle
> 
> 
> 
> 
> 
> 
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Bill Long                                                                       longb at cray.com
Fortran Technical Suport  &                                  voice:  651-605-9024
Bioinformatics Software Development                     fax:  651-605-9142
Cray Inc./ Cray Plaza, Suite 210/ 380 Jackson St./ St. Paul, MN 55101





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