(j3.2006) Question about macro concatenation

[Aleksandar Donev]

On Tuesday 05 December 2006 13:24, you wrote:

> I think the
> answer is no, because ?
> ????????B=1
> is not a lexical token (it is 3 lexical tokens) and therefore cannot
> sit by itself between two concatenation operators.
On second thought, parsing the bnf would seem to get from

A%%B=1%%3

result-token-1 result-token-2 result-token-3

where the second result-token is the equals. And then it is fine, it produces:

AB=13

The concatentation A%%X%%3 would also seem to work the same way when X gets 
replaced with "B=1". I repeat: Horrid!

Aleks